Write down the mechanism of basic hydrolysis of ester
Welcome to Answerclub.org
Questions | Answers | Discussions | Knowledge sharing | Communities & more.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
Questions | Answers | Discussions | Knowledge sharing | Communities & more.
Mechanism of Base Hydrolysis of Esters
The electrophilic reagent that is present is attacked by hydroxide nucleotides at C=0; thus creating the tetrahedral intermediate.
Mechanism of ester hydrolysis with NaOH
Step 1: Attack of Nucleophile
In the first step, the hydroxide ion attacks the electron-deficient carbon centre of the ester. It breaks the C=O π bond of ester and forms a tetrahedral intermediate structure.
Step 2: Elimination of Leaving Group
In the second step, an internal attack of O– ion takes place, reforming the C=O bond, leading to loss of alkoxide (RO–) ion.
Step 3: Deprotonation of Carboxylic Acid
In the third step, an acid-base equilibrium is set up between carboxylic acid and alcohol. Alkoxide (RO–) ion works as a base; it deprotonates the carboxylic acid, thus leading to the formation of alcohol and carboxylate ion.
Mechanism of ester hydrolysis with NaOH