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Sikta Roy
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Asked: 2024-03-17T17:40:40+05:30 In:

Two friends A and B are employed to do a piece of work in 18 days. If A is twice as efficient as B, find the time taken by each friend to do the work alone.

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Two friends A and B are employed to do a piece of work in 18 days. If A is twice as efficient as B, find the time taken by each friend to do the work alone.
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  1. Sikta Roy
    Knowledge Contributor

    Let the efficiency of B be 1 unit / day.
    Efficiency of A = 2 unit / day.
    Combined efficiency of A and B = 2+1 = 3 units / day
    Total work = No. of Days x Efficiency = 18 days x 3 units / day = 54 units
    Therefore, time required by A to complete the work alone = 54/2 = 27 days
    Time required by B to complete the work alone = 54/1 = 54 days

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