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Find the value of 5/(3 + 3/(1 – 2/3))
Let the value be x. x = 5/(3 + 3/(1 - 2/3)) = 5/(3 + 3/((3 - 2)/3)) = 5/(3 + 3/(1/3) = 5/(3 + 9) = 5/12 Answer: The value x is 5/12.
Let the value be x.
See lessx = 5/(3 + 3/(1 – 2/3))
= 5/(3 + 3/((3 – 2)/3))
= 5/(3 + 3/(1/3)
= 5/(3 + 9)
= 5/12
Answer: The value x is 5/12.
Arrange 7/9, 5/8, and 3/7 in the descending order.
7/9 = 0.78 5/8 = 0.625 3/7 = 0.428 Clearly, 0.78 > 0.625 > 0.428 Therefore, 7/9 > 5/8 > 3/7 Answer: 7/9 > 5/8 > 3/7.
7/9 = 0.78
5/8 = 0.625
3/7 = 0.428
Clearly, 0.78 > 0.625 > 0.428
Therefore, 7/9 > 5/8 > 3/7
Answer: 7/9 > 5/8 > 3/7.
See lessIn certain time a sum becomes 4 times at the rate of 5% per annum. At what rate of simple interest the same sum becomes 8 times in the same duration?
Case I, Principal = Rs. x Interest = 4x - x = Rs. 3x Therefore, Time = (S.I. × 100)/(Principal × Rate) = (3x × 100)/(x × 5) = 60 years Case II, Time = 60 years Interest = Rs. 7x Therefore, Rate = (Interest × 100)/(Principal × Time) = (7x × 100)/(x × 60) = 35/3 = 11 2/3% per annum Answer: At 11 2/3%Read more
Case I,
See lessPrincipal = Rs. x
Interest = 4x – x = Rs. 3x
Therefore, Time = (S.I. × 100)/(Principal × Rate)
= (3x × 100)/(x × 5) = 60 years
Case II,
Time = 60 years
Interest = Rs. 7x
Therefore, Rate = (Interest × 100)/(Principal × Time)
= (7x × 100)/(x × 60)
= 35/3
= 11 2/3% per annum
Answer: At 11 2/3% of simple interest the same sum becomes 8 times in the same duration.
The population of city increase at the rate of 5% per annum. If the present population of the city is 185220, what was its population 3 years ago?
P = P0 (1 + R/100)^T => 185220 = P0 (1 + 5/100)^3 => 185220 = P0 (21/20)^3 => P0 = (185220 × 20 × 20 × 20)/(21 × 21 × 21) => P0 = 160000 Answer: 3 years ago its population was 160000.
P = P0 (1 + R/100)^T
See less=> 185220 = P0 (1 + 5/100)^3
=> 185220 = P0 (21/20)^3
=> P0 = (185220 × 20 × 20 × 20)/(21 × 21 × 21)
=> P0 = 160000
Answer: 3 years ago its population was 160000.
Find the value of 12 of 26% of 5/78 of 38% of 7/152 of 10000.
Let the value be x. x = 12 × 26/100 × 5/78 × 38/100 × 7/152 × 10000 = 35 Answer: The value x is 35.
Let the value be x.
See lessx = 12 × 26/100 × 5/78 × 38/100 × 7/152 × 10000
= 35
Answer: The value x is 35.
Calculate the average of the cubes of first five natural numbers?
Required average = (1^3 + 2^3 + 3^3 + 4^3 + 5^3)/5 = (1 + 8 + 27 + 64 + 125)/5 = 225/5 = 45 Answer: The average of the cubes of first five natural numbers is 45.
Required average
See less= (1^3 + 2^3 + 3^3 + 4^3 + 5^3)/5
= (1 + 8 + 27 + 64 + 125)/5
= 225/5 = 45
Answer: The average of the cubes of first five natural numbers is 45.
A chair is bought for Rs. 3000 and sold at a loss of 6%. Find its selling price.
S.P. of chair = Rs. (3000 × 94/100) = Rs. 2820 Answer: Its selling price is Rs. 2820.
S.P. of chair
See less= Rs. (3000 × 94/100)
= Rs. 2820
Answer: Its selling price is Rs. 2820.
What would be the compound interest on ₹ 3200 at 25% per annum for 3 years?
C.I. = P[(1 + R/100)^T - 1] = 3200 [(1 + 25/100)^3 - 1] = 3200 [(1 + 1/4)^3 - 1] = 3200 [(5/4)^3 - 1] = 3200 [(125/64 - 1)] = 3200 × 61/64 = Rs. 3050
C.I. = P[(1 + R/100)^T – 1]
See less= 3200 [(1 + 25/100)^3 – 1]
= 3200 [(1 + 1/4)^3 – 1]
= 3200 [(5/4)^3 – 1]
= 3200 [(125/64 – 1)]
= 3200 × 61/64
= Rs. 3050
Find the value of (0.9% of 450) ÷ (0.2% of 250)
Let the value be x. x = (0.9 × 450)/100 ÷ (0.2 × 250)/100 = 4.05 ÷ 50/100 = 4.05 ÷ 0.5 = 8.1 Answer: The value x is 8.1.
Let the value be x.
See lessx = (0.9 × 450)/100 ÷ (0.2 × 250)/100
= 4.05 ÷ 50/100
= 4.05 ÷ 0.5
= 8.1
Answer: The value x is 8.1.
The average age of 3 friends is 23 years. Even if the age of 4th friend is added, the average remains 23 years. What is the age of the 4th friend?
Age of fourth friend = 23 × 4 - 23 × 3 = 23 (4 - 3) = 23 years Answer: 23 years is the age of the 4th friend.
Age of fourth friend
See less= 23 × 4 – 23 × 3
= 23 (4 – 3)
= 23 years
Answer: 23 years is the age of the 4th friend.