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  1. Asked: May 30, 2024In: Education

    Atmospheric pressure varies with

    Venkata chalapathi naidu
    Venkata chalapathi naidu Knowledge Contributor
    Added an answer on May 30, 2024 at 11:23 pm

    The atmospheric pressure varies with altitude as the density of air decreases as we rise up and the air becomes rarer. For example Pressure at sea level is taken as 76 cm of Mercury Column, which is one atmosphere. For every 105m rise in height, pressure decreases by 1 cm of mercury column.

    The atmospheric pressure varies with altitude as the density of air decreases as we rise up and the air becomes rarer. For example Pressure at sea level is taken as 76 cm of Mercury Column, which is one atmosphere. For every 105m rise in height, pressure decreases by 1 cm of mercury column.

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  2. Asked: May 30, 2024In: Education

    Dimensions of the dynamic viscosity (μ) are

    Venkata chalapathi naidu
    Venkata chalapathi naidu Knowledge Contributor
    Added an answer on May 30, 2024 at 11:23 pm

    dimensions. The dimensions of dynamic viscosity are force × time ÷ area. The unit of viscosity, accordingly, is newton-second per square metre, which is usually expressed as pascal-second in SI units.

    dimensions. The dimensions of dynamic viscosity are force × time ÷ area. The unit of viscosity, accordingly, is newton-second per square metre, which is usually expressed as pascal-second in SI units.

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  3. Asked: May 30, 2024In: Education

    A jet projected at an angle of 45θ, 40 m from the foot of a vertical column, just reaches the top of the column. The height of the column is

    Venkata chalapathi naidu
    Venkata chalapathi naidu Knowledge Contributor
    Added an answer on May 30, 2024 at 11:21 pm

    From any point jet has departed 45° and reaches the height of column (H). The distance between from any point to the tip of the column is 40m. ... Tan(45°) = H/40

    From any point jet has departed 45° and reaches the height of column (H). The distance between from any point to the tip of the column is 40m. … Tan(45°) = H/40

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  4. Asked: May 30, 2024In: Education

    To avoid vapourisation, pipe lines are laid over the ridge so that these are above the hydraulic gradient line, not more than

    Venkata chalapathi naidu
    Venkata chalapathi naidu Knowledge Contributor
    Added an answer on May 30, 2024 at 11:19 pm

    In order to avoid vaporization in the pipeline, the pipeline over the ridge is laid in such a way that it is not more than 6.4 m above the hydraulic gradient.

    In order to avoid vaporization in the pipeline, the pipeline over the ridge is laid in such a way that it is not more than 6.4 m above the hydraulic gradient.

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  5. Asked: May 30, 2024In: Education

    Which one of the following equation is applicable to unsteady flow in open channels :

    Venkata chalapathi naidu
    Venkata chalapathi naidu Knowledge Contributor
    Added an answer on May 30, 2024 at 11:16 pm

    By virtue of its free surface, unsteady channel flow is essentially non-uniform flow and it can therefore be conveniently considered in two categories, gradually varied and rapidly varied unsteady flow. Such a classification is made on the same basis as that used for steady non-uniform flow.

    By virtue of its free surface, unsteady channel flow is essentially non-uniform flow and it can therefore be conveniently considered in two categories, gradually varied and rapidly varied unsteady flow. Such a classification is made on the same basis as that used for steady non-uniform flow.

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  6. Asked: May 30, 2024In: Education

    An error of 1% in measuring the head of water over the crest of a triangular notch, produces an error in the discharge which is equal to

    Venkata chalapathi naidu
    Venkata chalapathi naidu Knowledge Contributor
    Added an answer on May 30, 2024 at 11:15 pm

    Therefore, an error of 1% in measuring H will produce an error of 0.00436% in discharge over a triangular notch. Conclusion: Hence, the correct option is D) 2.5% which is the closest option to the calculated error in discharge over a triangular notch.

    Therefore, an error of 1% in measuring H will produce an error of 0.00436% in discharge over a triangular notch. Conclusion: Hence, the correct option is D) 2.5% which is the closest option to the calculated error in discharge over a triangular notch.

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  7. Asked: May 30, 2024In: Education

    A cylindrical vessel 40 cm high is revolved about its vertical axis so that the water touches the bottom when it just spills out. If the radius of the cylinder is 5 cm, the angular velocity of rotation, is

    Venkata chalapathi naidu
    Venkata chalapathi naidu Knowledge Contributor
    Added an answer on May 30, 2024 at 11:12 pm

    NEWTON'S LAW OF VISCOSITY: The ratio of shear stress(τ) to the rate of shear strain(du/dy) is a constant and is known as viscosity or coefficient of viscosity(µ).

    NEWTON’S LAW OF VISCOSITY: The ratio of shear stress(τ) to the rate of shear strain(du/dy) is a constant and is known as viscosity or coefficient of viscosity(µ).

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  8. Asked: May 30, 2024In: Education

    In Newton's viscosity equation , the coefficient (μ) is known as coefficient of

    Venkata chalapathi naidu
    Venkata chalapathi naidu Knowledge Contributor
    Added an answer on May 30, 2024 at 11:12 pm

    NEWTON'S LAW OF VISCOSITY: The ratio of shear stress(τ) to the rate of shear strain(du/dy) is a constant and is known as viscosity or coefficient of viscosity(µ).

    NEWTON’S LAW OF VISCOSITY: The ratio of shear stress(τ) to the rate of shear strain(du/dy) is a constant and is known as viscosity or coefficient of viscosity(µ).

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  9. Asked: May 30, 2024In: Education

    For the flow of liquid from an open ended tube (or nozzle) leading to the formation of spray of liquid drops, the number generally applied, is

    Venkata chalapathi naidu
    Venkata chalapathi naidu Knowledge Contributor
    Added an answer on May 30, 2024 at 11:11 pm

    The depth of oil column exerting the pressure of is 60 m. specific gravity=0.8.

    The depth of oil column exerting the pressure of is 60 m. specific gravity=0.8.

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  10. Asked: May 30, 2024In: Education

    For exerting a pressure of 4.8 kg/cm2, the depth of oil (specific gravity 0.8), should be

    Venkata chalapathi naidu
    Venkata chalapathi naidu Knowledge Contributor
    Added an answer on May 30, 2024 at 11:10 pm

    Expert-Verified Answer The depth of oil column exerting the pressure of is 60 m. specific gravity=0.8.

    Expert-Verified Answer
    The depth of oil column exerting the pressure of is 60 m. specific gravity=0.8.

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