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The flow in open channel is said to be critical if the Froude number is :
With such a definition, Fr = 1 at critical flow conditions. 3. In open channel flows, it is strongly advised to define the Froude number such as Fr = 1 at critical flow conditions. That is, Fr dc) and Fr > 1 for supercritical flow (d < dc).
With such a definition, Fr = 1 at critical flow conditions. 3. In open channel flows, it is strongly advised to define the Froude number such as Fr = 1 at critical flow conditions. That is, Fr dc) and Fr > 1 for supercritical flow (d < dc).
See lessAn orifice is an opening in a vessel with
Orifice: An opening, in a vessel, through which the liquid flows out is known as an orifice. This hole or opening is called an orifice, so long as the level of the liquid on the upstream side is above the top of the orifice.
Orifice: An opening, in a vessel, through which the liquid flows out is known as an orifice. This hole or opening is called an orifice, so long as the level of the liquid on the upstream side is above the top of the orifice.
See lessEquation of continuity of fluids is applicable only if
The continuity equation applies to all fluids, compressible and incompressible flow, Newtonian and non-Newtonian fluids. It expresses the law of conservation of mass at each point in a fluid and must therefore be satisfied at every point in a flow field.
The continuity equation applies to all fluids, compressible and incompressible flow, Newtonian and non-Newtonian fluids. It expresses the law of conservation of mass at each point in a fluid and must therefore be satisfied at every point in a flow field.
See lessIf v1 and v2 are the velocities of flow before and after sudden enlargement in a pipe, the head loss given by Carnot and Borda equation, is
Sudden expansion loss: ( h L ) e x p = ( v 1 − v 2 ) 2 2 g.
Sudden expansion loss: ( h L ) e x p = ( v 1 − v 2 ) 2 2 g.
See lessFor steady flow in open channels, which one of the following does not change :
The flow depth does not change with time at every cross-section and at the same time is constant along the flow direction. The depth of flow will be constant along the channel length and hence the free surface will be parallel to the bed.
The flow depth does not change with time at every cross-section and at the same time is constant along the flow direction. The depth of flow will be constant along the channel length and hence the free surface will be parallel to the bed.
See lessThe most efficient channel section, is
Compared to other cross-sections, the semicircular section has the lowest wetted perimeter, and is, therefore, the section of the highest efficiency, but, due to practical limitations in maintaining the section, trapezoidal channels are usually employed.
Compared to other cross-sections, the semicircular section has the lowest wetted perimeter, and is, therefore, the section of the highest efficiency, but, due to practical limitations in maintaining the section, trapezoidal channels are usually employed.
See lessOne metric slug is equal to
32.17405 lb One slug is a mass equal to 32.17405 lb (14.59390 kg) based on standard gravity, the international foot, and the avoirdupois pound. In other words, at the Earth's surface (in standard gravity), an object with a mass of 1 slug weighs approximately 32.17405 lbf or 143.1173 N.
32.17405 lb
See lessOne slug is a mass equal to 32.17405 lb (14.59390 kg) based on standard gravity, the international foot, and the avoirdupois pound. In other words, at the Earth’s surface (in standard gravity), an object with a mass of 1 slug weighs approximately 32.17405 lbf or 143.1173 N.
Falling drops of water become spheres due to
Because of a phenomenon known as surface tension, water drops, or any other liquid's drops, are spherical in shape. This acts on the surface of a freely falling drop in a liquid to reduce its area.
Because of a phenomenon known as surface tension, water drops, or any other liquid’s drops, are spherical in shape. This acts on the surface of a freely falling drop in a liquid to reduce its area.
See lessThe formula Q = m x L x 2g x H3/2 where was suggested by :
q = 0.415 (L - 0.2 h.) ho^1.5 (2g)^1\2 Where: q = volumetric flow rate, ft / s L = height of crest, ft ho = height of fall of the weir.
q = 0.415 (L – 0.2 h.) ho^1.5 (2g)^1\2 Where: q = volumetric flow rate, ft / s L = height of crest, ft ho = height of fall of the weir.
See lessThe value of kinetic energy correction factor (a) for a laminar flow through a circular pipe, is
around 2 where is the Kinetic Energy Factor. Its value for a fully developed laminar pipe flow is around 2, whereas for a turbulent pipe flow it is between 1.04 to 1.11.
around 2
See lesswhere is the Kinetic Energy Factor. Its value for a fully developed laminar pipe flow is around 2, whereas for a turbulent pipe flow it is between 1.04 to 1.11.