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What do you mean by alkalinity?
Alkalinity is the capacity of water for neutralizing an acid solution. or. Alkalinity is a measure of the capacity of water or any solution to neutralize or 'buffer' acids. The ability to resist changes in pH by neutralizing acids or bases is called buffering.
Alkalinity is the capacity of water for neutralizing an acid solution. or. Alkalinity is a measure of the capacity of water or any solution to neutralize or ‘buffer’ acids. The ability to resist changes in pH by neutralizing acids or bases is called buffering.
See lessHow to make 2M NaOH?
Place 100 mL of distilled and degassed water in a volumetric flask of 1 L volume. Then accurately weigh approximately 80 g of NaOH (equivalent to 2 mol of substance) in a weighing boat on an analytical balance and transfer it to the volumetric flask (use a solid funnel).
Place 100 mL of distilled and degassed water in a volumetric flask of 1 L volume. Then accurately weigh approximately 80 g of NaOH (equivalent to 2 mol of substance) in a weighing boat on an analytical balance and transfer it to the volumetric flask (use a solid funnel).
See lessHow to make 0.1 M HCl?
I would put about 400 mL of water in a beaker and slowly add the HCl to that with stirring. Then, add more water to give the final volume. So, carefully diluting 47.2 mL of 36% HCl to a final volume of 500 mL will give you 0.1 M HCl.
I would put about 400 mL of water in a beaker and slowly add the HCl to that with stirring. Then, add more water to give the final volume. So, carefully diluting 47.2 mL of 36% HCl to a final volume of 500 mL will give you 0.1 M HCl.
See lessHow to prepare 1m H2SO4 in 100ml?
= m a s s ρ = 10 1.84 = 5.43 m l . So, 5.43ml of the acid(98% by mass) have to take in a 100ml volumetric then dilute it to 100ml.
= m a s s ρ = 10 1.84 = 5.43 m l . So, 5.43ml of the acid(98% by mass) have to take in a 100ml volumetric then dilute it to 100ml.
See lessHow to prepare 2M HCl?
How can we prepare a solution of 2 molar hydrochloric acid in one liter? HCl can be obtained with different concentrations of HCL in water. V1 = 1*2/12.2 = 0.164 L or 164 mL of 12.2M HCl diluted to 1 Liter with water will yield a 2M solution.
How can we prepare a solution of 2 molar hydrochloric acid in one liter? HCl can be obtained with different concentrations of HCL in water. V1 = 1*2/12.2 = 0.164 L or 164 mL of 12.2M HCl diluted to 1 Liter with water will yield a 2M solution.
See lessHow do you make 100ml dilute sulphuric acid?
Add 5.5 mL of sulfuric acid to 60 mL of water, allow to cool and add sufficient water to produce 100 mL.
Add 5.5 mL of sulfuric acid to 60 mL of water, allow to cool and add sufficient water to produce 100 mL.
See lessHow to dilute 85 phosphoric acid to 25?
Assuming 100mL of 85%, and with “X” as the volume of water to add, you set up the equation: [(100 * 1.69) + (X * 1.0)] = [(100+X)*(1.15)] and solve for X, which gives you X = 360mL. So for one liter of 25% phos, you would need [1000/(360+100)]*360 = 782 mL of water to which you will add (1000-782) =Read more
Assuming 100mL of 85%, and with “X” as the volume of water to add, you set up the equation: [(100 * 1.69) + (X * 1.0)] = [(100+X)*(1.15)] and solve for X, which gives you X = 360mL. So for one liter of 25% phos, you would need [1000/(360+100)]*360 = 782 mL of water to which you will add (1000-782) = 218 ml of 85% phos.
See lessHow to make 0.1 N HCl?
Procedure for Preparing 0.1 N HCl solution Add 8.1744 (about 8.2 mL of 37% concentrated HCl) carefully. Pour in 700mL of water. Allow the solution to cool to room temperature. Add the distilled water to increase the volume up to 1000 mL.
Procedure for Preparing 0.1 N HCl solution
Add 8.1744 (about 8.2 mL of 37% concentrated HCl) carefully. Pour in 700mL of water. Allow the solution to cool to room temperature. Add the distilled water to increase the volume up to 1000 mL.
See lessHow to dilute 98% sulphuric acid?
How to dilute 98% sulphuric acid? Generally 98% sulfuric acid is sold in the market so use dilution formula, say for example we wish to prepare 100 ml of 10% volume by volume solution. then. 98% X ml? = ... X ml= 1000/98 = 10.20ml. now add 89.8ml of water in 100 ml volumetric flask then add 10.20 mlRead more
How to dilute 98% sulphuric acid?
See lessGenerally 98% sulfuric acid is sold in the market so use dilution formula, say for example we wish to prepare 100 ml of 10% volume by volume solution.
then.
98% X ml? = …
X ml= 1000/98 = 10.20ml.
now add 89.8ml of water in 100 ml volumetric flask then add 10.20 ml sulfuric acid
How to prepare 8% HCl?
Fill a 1 L volumetric flask with about 300 mL of distilled water. Carefully and slowly add the 667 mL of HCl to the flask in increments. This will generate a lot of heat and caustic fumes. Fill the volumetric flask to the 1 L line with distilled water.
Fill a 1 L volumetric flask with about 300 mL of distilled water. Carefully and slowly add the 667 mL of HCl to the flask in increments. This will generate a lot of heat and caustic fumes. Fill the volumetric flask to the 1 L line with distilled water.
See less