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  1. Asked: May 31, 2024In: Education

    The value of momentum correction factor (β) for a laminar flow through a circular pipe, is

    Kavya T
    Kavya T Knowledge Contributor
    Added an answer on May 31, 2024 at 3:43 pm

    Momentum correction factor is defined as the ratio of momentum of the flow per second based on actual velocity to the momentum of the flow per second based on average velocity across a section. For turbulent flow the momentum correction factor is slightly higher than one near to 1.2 and for laminar,Read more

    Momentum correction factor is defined as the ratio of momentum of the flow per second based on actual velocity to the momentum of the flow per second based on average velocity across a section. For turbulent flow the momentum correction factor is slightly higher than one near to 1.2 and for laminar, its value is 1.33

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  2. Asked: May 31, 2024In: Education

    Manometers are used to measure

    Kavya T
    Kavya T Knowledge Contributor
    Added an answer on May 31, 2024 at 3:42 pm

    A manometer is a device that we use to measure the pressure of the pipelines (cab be of gas, water, liquid, etc.) Also, it is usually referred to as a U-shaped tube that is filled with a liquid.

    A manometer is a device that we use to measure the pressure of the pipelines (cab be of gas, water, liquid, etc.) Also, it is usually referred to as a U-shaped tube that is filled with a liquid.

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  3. Asked: May 31, 2024In: Education

    The equation for the viscosity, is suggested

    Kavya T
    Kavya T Knowledge Contributor
    Added an answer on May 31, 2024 at 3:42 pm

    This formula also shows that this all equals F/A. Recall that viscosity is equal to force divided by area; the F refers to force and the A refers to area. Therefore, F/A is another way to refer to viscosity.

    This formula also shows that this all equals F/A. Recall that viscosity is equal to force divided by area; the F refers to force and the A refers to area. Therefore, F/A is another way to refer to viscosity.

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  4. Asked: May 31, 2024In: Education

    In an open tube, free surface of mercury remains

    Kavya T
    Kavya T Knowledge Contributor
    Added an answer on May 31, 2024 at 3:42 pm

    Explanation: Assuming the test tube is made of glass, the mercury has obtuse angle of contact. Hence, the outer surface will be convex, unlike water (which has concave surface due to acute contact angle).

    Explanation: Assuming the test tube is made of glass, the mercury has obtuse angle of contact. Hence, the outer surface will be convex, unlike water (which has concave surface due to acute contact angle).

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  5. Asked: May 31, 2024In: Education

    Most economical section of a triangular channel, is

    Kavya T
    Kavya T Knowledge Contributor
    Added an answer on May 31, 2024 at 3:40 pm

    In the most economical triangular section, the side slope has to be inclined at 45∘ or the hydraulic radius has to be 1 2 2 times the depth of flow. The width of the channel is twice the depth of flow. Hydraulic radius is half of the depth of flow.

    In the most economical triangular section, the side slope has to be inclined at 45∘ or the hydraulic radius has to be 1 2 2 times the depth of flow. The width of the channel is twice the depth of flow. Hydraulic radius is half of the depth of flow.

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  6. Asked: May 30, 2024In: Education

    When a body is totally or partially immersed in a fluid, it is buoyed up by a force equal to

    Kavya T
    Kavya T Knowledge Contributor
    Added an answer on May 30, 2024 at 8:20 pm

    Any object, totally or partially immersed in a fluid or liquid, is buoyed up by a force equal to the weight of the fluid displaced by the object.

    Any object, totally or partially immersed in a fluid or liquid, is buoyed up by a force equal to the weight of the fluid displaced by the object.

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  7. Asked: May 30, 2024In: Education

    Reynold number is the ratio of initial force and

    Kavya T
    Kavya T Knowledge Contributor
    Added an answer on May 30, 2024 at 8:20 pm

    Reynold's number: It is a dimensionless number that determines the nature of the flow of liquid through a pipe. It is defined as the ratio of the inertial force to the viscous force for a flowing fluid.

    Reynold’s number: It is a dimensionless number that determines the nature of the flow of liquid through a pipe. It is defined as the ratio of the inertial force to the viscous force for a flowing fluid.

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  8. Asked: May 30, 2024In: Education

    Euler's equation for motion of liquids, is given by

    Kavya T
    Kavya T Knowledge Contributor
    Added an answer on May 30, 2024 at 8:19 pm

    Euler's Equation, proposed by Leonhard Euler in the mid-18th Century, is a vital equation in fluid mechanics that describes the flow of inviscid fluid. Here, inviscid fluid refers to an ideal fluid with zero viscosity.

    Euler’s Equation, proposed by Leonhard Euler in the mid-18th Century, is a vital equation in fluid mechanics that describes the flow of inviscid fluid. Here, inviscid fluid refers to an ideal fluid with zero viscosity.

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  9. Asked: May 30, 2024In: Education

    An ideal flow of a liquid obeys

    Kavya T
    Kavya T Knowledge Contributor
    Added an answer on May 30, 2024 at 8:17 pm

    An ideal flow of any fluid must fulfill the “Continuity equation”. The continuity equation applies to all fluids whether incompressible (ideal) or compressible (non-ideal), Newtonian or non-Newtonian fluids.

    An ideal flow of any fluid must fulfill the “Continuity equation”. The continuity equation applies to all fluids whether incompressible (ideal) or compressible (non-ideal), Newtonian or non-Newtonian fluids.

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  10. Asked: May 30, 2024In: Education

    A pipe of 0.1 m2 cross sectional area suddenly enlarges to 0.3 m2 cross-sectional area. If the discharge of the pipe is 0.3 m3 /sec, the head loss is

    Kavya T
    Kavya T Knowledge Contributor
    Added an answer on May 30, 2024 at 8:16 pm

    The velocity in the larger pipe is: v2 = Q / A2 = 0.3 m^3/s / 0.3 m^2 = 1 m/s h(en) = (v1 - v2)^2 / 2g = (3 m/s - 1 m/s)^2 / 2 * 9.81 m/s^2 = 2/g meters of water Therefore, the head loss is 2/g meters of water.

    The velocity in the larger pipe is:

    v2 = Q / A2 = 0.3 m^3/s / 0.3 m^2 = 1 m/s

    h(en) = (v1 – v2)^2 / 2g = (3 m/s – 1 m/s)^2 / 2 * 9.81 m/s^2 = 2/g meters of water

    Therefore, the head loss is 2/g meters of water.

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